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ejemplos de combinaciones de mysql

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Ejemplo 1: consulta de combinación de mysql

SELECT 
    m.member_id, 
    m.name member, 
    c.committee_id, 
    c.name committee
FROM
    members m
INNERJOIN committees c 
	ON c.name = m.name;

Ejemplo 2: MySQL Join

A relational database consists of multiple related tables linking together using common columns which are known asforeignkeycolumns. Because of this,datain each tableis incomplete from the business perspective.
MySQL supports the followingtypesof joins:

InnerjoinLeftjoinRightjoinCrossjoin

The following shows the basic syntax of the innerjoin clause that joins two tables table_1 and table_2:

SELECT column_list
FROM table_1
INNERJOIN table_2 ON join_condition;SELECT column_list
FROM table_1
INNERJOIN table_2 USING(column_name);SELECT column_list 
FROM table_1 
LEFTJOIN table_2 USING(column_name);
Here is the syntax of the rightjoin:

SELECT column_list 
FROM table_1 
RIGHTJOIN table_2 ON join_condition;

The following shows the basic syntax of the crossjoin clause:

SELECT select_list
FROM table_1
CROSSJOIN table_2;

Ejemplo 3: tipos de combinaciones en mysql

Joins are used withselect statement. it is used toselectdatafrom multiple table.Types:
MySQL INNERJOIN(orsimplejoin)
MySQL LEFTOUTERJOIN(orLEFTJOIN)
MySQL RIGHTOUTERJOIN(orRIGHTJOIN)InnerJOIN :
The INNERJOINis used toreturnallrowsfrom multiple tableswhere the join condition is satisfied. It is the most common typeofjoin.LeftOuterJoin:
The LEFTOUTERJOINreturnsallrowsfrom the left hand table specified in the ON condition and only those rowsfrom the other tablewhere the join condition is fulfilled.RightOuterJoin:
The RightOuterJoinreturnsallrowsfrom the RIGHT-hand table specified in the ON condition and only those rowsfrom the other tablewhere he join condition is fulfilled.

Ejemplo 4: mysql two joins

SELECT areas.name AS aname,COUNT(consultants.active)AS cct 
    FROM areas 
    LEFTJOIN consAreas 
      ON consAreas.area = areas.id 
    LEFTJOIN consultants 
      ON consultants.id = consAreas.cons
   WHERE areas.areaID = $area 
     AND consultants.active =1GROUPBY areas.name
ORDERBY areas.name

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