Ejemplo de código de función de jquery ajax done

Basta ya de indagar por todo internet porque has llegado al sitio exacto, contamos con la solución que deseas pero sin problemas.

Ejemplo: hacer llamadas ajax con jQuery

// GET Request
    $.ajax(
        url:"example.php?firstParam=Hello&secondParam=World",//you can also pass get parameters
        dataType:'json',//dataType you expect in the response from the server
        timeout:2000).done(function(data, textStatus, jqXHR)//your code here).fail(function(jqXHR, textStatus, errorThrown)console.log("jqXHR:"+ jqXHR);console.log("TestStatus: "+ textStatus);console.log("ErrorThrown: "+ errorThrown););//POST Requestvar formData =name:"John", surname:"Doe", age:"31";//Array 
    $.ajax(
        url:"example.php",
        type:"POST",// data type (can be get, post, put, delete)
        data: formData,// data in json format
       	timeout:2000,//Is useful ONLY if async=true. If async=false it is useless
        async:false,// enable or disable async (optional, but suggested as false if you need to populate data afterwards)success:function(data, textStatus, jqXHR)//your code here,error:function(jqXHR, textStatus, errorThrown)console.log("jqXHR:"+ jqXHR);console.log("TestStatus: "+ textStatus);console.log("ErrorThrown: "+ errorThrown););//Alternatively, the old aproach is
    $.ajax(
        url:"api.php?action=getCategories",
        dataType:'json',
        timeout:2000,success:function(result, textStatus, jqXHR)//jqXHR = jQuery XMLHttpRequest/*You could put your code here but this way of doing it is obsolete. Better to use .done()*/,error:function(jqXHR, textStatus, errorThrown)console.log("jqXHR:"+ jqXHR);console.log("TestStatus: "+ textStatus);console.log("ErrorThrown: "+ errorThrown););

Recuerda que puedes mostrar esta noticia si te valió la pena.

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