convertir un archivo xml en un diccionario de ejemplo de código python

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Ejemplo: Python convierte XML a diccionario

from xml.etree import cElementTree as ElementTree

classXmlListConfig(list):def__init__(self, aList):for element in aList:if element:# treat like dictiflen(element)==1or element[0].tag != element[1].tag:
                    self.append(XmlDictConfig(element))# treat like listelif element[0].tag == element[1].tag:
                    self.append(XmlListConfig(element))elif element.text:
                text = element.text.strip()if text:
                    self.append(text)classXmlDictConfig(dict):'''
    Example usage:

    >>> tree = ElementTree.parse('your_file.xml')
    >>> root = tree.getroot()
    >>> xmldict = XmlDictConfig(root)

    Or, if you want to use an XML string:

    >>> root = ElementTree.XML(xml_string)
    >>> xmldict = XmlDictConfig(root)

    And then use xmldict for what it is... a dict.
    '''def__init__(self, parent_element):if parent_element.items():
            self.update(dict(parent_element.items()))for element in parent_element:if element:# treat like dict - we assume that if the first two tags# in a series are different, then they are all different.iflen(element)==1or element[0].tag != element[1].tag:
                    aDict = XmlDictConfig(element)# treat like list - we assume that if the first two tags# in a series are the same, then the rest are the same.else:# here, we put the list in dictionary; the key is the# tag name the list elements all share in common, and# the value is the list itself 
                    aDict =element[0].tag: XmlListConfig(element)# if the tag has attributes, add those to the dictif element.items():
                    aDict.update(dict(element.items()))
                self.update(element.tag: aDict)# this assumes that if you've got an attribute in a tag,# you won't be having any text. This may or may not be a # good idea -- time will tell. It works for the way we are# currently doing XML configuration files...elif element.items():
                self.update(element.tag:dict(element.items()))# finally, if there are no child tags and no attributes, extract# the textelse:
                self.update(element.tag: element.text)

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