Basta ya de indagar por otras páginas ya que llegaste al espacio adecuado, poseemos la respuesta que necesitas hallar y sin complicaciones.
Solución:
Simplemente divídalo en 3 partes … la primera semana, la semana pasada y las intermedias, algo como esto:
function workday_count(start,end)
var first = start.clone().endOf('week'); // end of first week
var last = end.clone().startOf('week'); // start of last week
var days = last.diff(first,'days') * 5 / 7; // this will always multiply of 7
var wfirst = first.day() - start.day(); // check first week
if(start.day() == 0) --wfirst; // -1 if start with sunday
var wlast = end.day() - last.day(); // check last week
if(end.day() == 6) --wlast; // -1 if end with saturday
return wfirst + Math.floor(days) + wlast; // get the total
// ^ EDIT: if days count less than 7 so no decimal point
El código de prueba
var ftest = date:'2015-02-0',start:1,end:7;
var ltest = date:'2015-02-2',start:2,end:8;
var f = 'YYYY-MM-DD';
for(var z=ftest.start; z<=ftest.end; ++z)
var start = moment(ftest.date + z);
for(var y=ltest.start; y<=ltest.end; ++y)
var end = moment(ltest.date + y);
var wd = workday_count(start,end);
console.log('from: '+start.format(f),'to: '+end.format(f),'is '+wd+' workday(s)');
Salida del código de prueba:
from: 2015-02-01 to: 2015-02-22 is 15 workday(s)
from: 2015-02-01 to: 2015-02-23 is 16 workday(s)
from: 2015-02-01 to: 2015-02-24 is 17 workday(s)
from: 2015-02-01 to: 2015-02-25 is 18 workday(s)
from: 2015-02-01 to: 2015-02-26 is 19 workday(s)
from: 2015-02-01 to: 2015-02-27 is 20 workday(s)
from: 2015-02-01 to: 2015-02-28 is 20 workday(s)
from: 2015-02-02 to: 2015-02-22 is 15 workday(s)
from: 2015-02-02 to: 2015-02-23 is 16 workday(s)
from: 2015-02-02 to: 2015-02-24 is 17 workday(s)
from: 2015-02-02 to: 2015-02-25 is 18 workday(s)
from: 2015-02-02 to: 2015-02-26 is 19 workday(s)
from: 2015-02-02 to: 2015-02-27 is 20 workday(s)
from: 2015-02-02 to: 2015-02-28 is 20 workday(s)
from: 2015-02-03 to: 2015-02-22 is 14 workday(s)
from: 2015-02-03 to: 2015-02-23 is 15 workday(s)
from: 2015-02-03 to: 2015-02-24 is 16 workday(s)
from: 2015-02-03 to: 2015-02-25 is 17 workday(s)
from: 2015-02-03 to: 2015-02-26 is 18 workday(s)
from: 2015-02-03 to: 2015-02-27 is 19 workday(s)
from: 2015-02-03 to: 2015-02-28 is 19 workday(s)
from: 2015-02-04 to: 2015-02-22 is 13 workday(s)
from: 2015-02-04 to: 2015-02-23 is 14 workday(s)
from: 2015-02-04 to: 2015-02-24 is 15 workday(s)
from: 2015-02-04 to: 2015-02-25 is 16 workday(s)
from: 2015-02-04 to: 2015-02-26 is 17 workday(s)
from: 2015-02-04 to: 2015-02-27 is 18 workday(s)
from: 2015-02-04 to: 2015-02-28 is 18 workday(s)
from: 2015-02-05 to: 2015-02-22 is 12 workday(s)
from: 2015-02-05 to: 2015-02-23 is 13 workday(s)
from: 2015-02-05 to: 2015-02-24 is 14 workday(s)
from: 2015-02-05 to: 2015-02-25 is 15 workday(s)
from: 2015-02-05 to: 2015-02-26 is 16 workday(s)
from: 2015-02-05 to: 2015-02-27 is 17 workday(s)
from: 2015-02-05 to: 2015-02-28 is 17 workday(s)
from: 2015-02-06 to: 2015-02-22 is 11 workday(s)
from: 2015-02-06 to: 2015-02-23 is 12 workday(s)
from: 2015-02-06 to: 2015-02-24 is 13 workday(s)
from: 2015-02-06 to: 2015-02-25 is 14 workday(s)
from: 2015-02-06 to: 2015-02-26 is 15 workday(s)
from: 2015-02-06 to: 2015-02-27 is 16 workday(s)
from: 2015-02-06 to: 2015-02-28 is 16 workday(s)
from: 2015-02-07 to: 2015-02-22 is 10 workday(s)
from: 2015-02-07 to: 2015-02-23 is 11 workday(s)
from: 2015-02-07 to: 2015-02-24 is 12 workday(s)
from: 2015-02-07 to: 2015-02-25 is 13 workday(s)
from: 2015-02-07 to: 2015-02-26 is 14 workday(s)
from: 2015-02-07 to: 2015-02-27 is 15 workday(s)
from: 2015-02-07 to: 2015-02-28 is 15 workday(s)
Utilizo una función simple para lograr eso. Quizás no sea el más eficiente pero funciona. No requiere Moment.js. es solo Javascript.
function getNumWorkDays(startDate, endDate)
var numWorkDays = 0;
var currentDate = new Date(startDate);
while (currentDate <= endDate)
// Skips Sunday and Saturday
if (currentDate.getDay() !== 0 && currentDate.getDay() !== 6)
numWorkDays++;
currentDate = currentDate.addDays(1);
return numWorkDays;
Para addDays, Uso la siguiente función:
Date.prototype.addDays = function (days)
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
;
Hice una adaptación a la respuesta de Kokizzu para solucionar un problema de horario de verano. En la zona horaria brasileña (GMT -3), la diferencia entre el 17/10/2017 y el 18/10/2017 fue -2,71 en lugar de 2.
El inicio de la semana fue el 15/10/2017 00:00 UTC o el 14/10/2017 21: 00-03: 00
El final de la semana fue el 22/10/2017 a las 00:00 UTC o el 21/10/2017 22: 00-02: 00 (horario de verano)
Por lo tanto, en lugar de 7, la diferencia entre la "primera" y la "última" variable en días fue 6 (u 8, según su zona horaria).
El código corregido está a continuación:
start = moment(start).utc().add(start.utcOffset(), 'm'); // Ignore timezones
end = moment(end).utc().add(end.utcOffset(), 'm'); // Ignore timezones
var first = start.clone().endOf('week'); // end of first week
var last = end.clone().startOf('week'); // start of last week
// Fixing Summer Time problems
firstCorrection = moment(first).utc().add(60, 'm').toDate(); //
var days = last.diff(firstCorrection,'days') * 5 / 7; // this will always multiply of 7
var wfirst = first.day() - start.day(); // check first week
if(start.day() == 0) --wfirst; // -1 if start with sunday
var wlast = end.day() - last.day(); // check last week
if(end.day() == 6) --wlast; // -1 if end with saturday
return wfirst + days + wlast; // get the total (subtract holidays if needed)
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