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Solución:
O(1) solución:
// Count days from d0 to d1 inclusive, excluding weekends
public static int countWeekDays(DateTime d0, DateTime d1)
int ndays = 1 + Convert.ToInt32((d1 - d0).TotalDays);
int nsaturdays = (ndays + Convert.ToInt32(d0.DayOfWeek)) / 7;
return ndays - 2 * nsaturdays
- (d0.DayOfWeek == DayOfWeek.Sunday ? 1 : 0)
+ (d1.DayOfWeek == DayOfWeek.Saturday ? 1 : 0);
Ejemplos para enero de 2014:
January 2014
Su Mo Tu We Th Fr Sa
1 2 3 4
5 6 7 8 9 10 11
12 13 14 15 16 17 18
19 20 21 22 23 24 25
26 27 28 29 30 31
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 1)); // 1
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 2)); // 2
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 3)); // 3
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 4)); // 3
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 5)); // 3
countWeekDays(new DateTime(2014, 1, 1), new DateTime(2014, 1, 6)); // 4
Nota: el DateTime las entradas deben ser aproximadamente a la misma hora del día. si estas creando DateTime objetos basados únicamente en año, mes y día como en los ejemplos anteriores, entonces debería estar bien. Como contraejemplo, de las 12:01 a. m. del 1 de enero a las 11:59 p. m. del 2 de enero se extienden solo 2 días, pero la función anterior contará 3 si usa esos tiempos.
Desde este enlace:
public static int Weekdays(DateTime dtmStart, DateTime dtmEnd)
// This function includes the start and end date in the count if they fall on a weekday
int dowStart = ((int)dtmStart.DayOfWeek == 0 ? 7 : (int)dtmStart.DayOfWeek);
int dowEnd = ((int)dtmEnd.DayOfWeek == 0 ? 7 : (int)dtmEnd.DayOfWeek);
TimeSpan tSpan = dtmEnd - dtmStart;
if (dowStart <= dowEnd)
return (((tSpan.Days / 7) * 5) + Math.Max((Math.Min((dowEnd + 1), 6) - dowStart), 0));
return (((tSpan.Days / 7) * 5) + Math.Min((dowEnd + 6) - Math.Min(dowStart, 6), 5));
[1]: http://www.eggheadcafe.com/community/aspnet/2/44982/how-to-calculate-num-of-w.aspx
Pruebas (cada prueba devuelve 5):
int ndays = Weekdays(new DateTime(2009, 11, 30), new DateTime(2009, 12, 4));
System.Console.WriteLine(ndays);
// leap year test
ndays = Weekdays(new DateTime(2000, 2,27), new DateTime(2000, 3, 5));
System.Console.WriteLine(ndays);
// non leap year test
ndays = Weekdays(new DateTime(2007, 2, 25), new DateTime(2007, 3, 4));
System.Console.WriteLine(ndays);
La respuesta de eFloh tenía un día extra si el último día era sábado o domingo. Esto lo arreglaría.
public static int Weekdays(DateTime dtmStart, DateTime dtmEnd)
if (dtmStart > dtmEnd)
DateTime temp = dtmStart;
dtmStart = dtmEnd;
dtmEnd = temp;
/* Move border dates to the monday of the first full week and sunday of the last week */
DateTime startMonday = dtmStart;
int startDays = 1;
while (startMonday.DayOfWeek != DayOfWeek.Monday)
if (startMonday.DayOfWeek != DayOfWeek.Saturday && startMonday.DayOfWeek != DayOfWeek.Sunday)
startDays++;
startMonday = startMonday.AddDays(1);
DateTime endSunday = dtmEnd;
int endDays = 0;
while (endSunday.DayOfWeek != DayOfWeek.Sunday)
if (endSunday.DayOfWeek != DayOfWeek.Saturday && endSunday.DayOfWeek != DayOfWeek.Sunday)
endDays++;
endSunday = endSunday.AddDays(1);
int weekDays;
/* calculate weeks between full week border dates and fix the offset created by moving the border dates */
weekDays = (Math.Max(0, (int)Math.Ceiling((endSunday - startMonday).TotalDays + 1)) / 7 * 5) + startDays - endDays;
if (dtmEnd.DayOfWeek == DayOfWeek.Saturday
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