Posterior a consultar expertos en este tema, programadores de varias áreas y maestros dimos con la solución a la pregunta y la dejamos plasmada en esta publicación.
Solución:
DOS TABLAS EN LA BASE DE DATOS ACTUAL
Si quieres saber si dos tablas son diferentes, ejecuta esto
SELECT IF(COUNT(1)>0,'Differences','No Differences') Comparison FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE table_schema=DATABASE()
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
Si realmente necesita ver las diferencias, ejecute esto
SELECT column_name,ordinal_position,data_type,column_type FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE table_schema=DATABASE()
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
DOS TABLAS EN UNA BASE DE DATOS ESPECÍFICA
Si desea saber si dos tablas son diferentes en la base de datos mydb
ejecuta esto
SELECT IF(COUNT(1)>0,'Differences','No Differences') Comparison FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE table_schema='mydb'
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
Si realmente necesita ver las diferencias, ejecute esto
SELECT column_name,ordinal_position,data_type,column_type FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE table_schema='mydb'
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
DOS TABLAS EN DOS BASES DE DATOS DIFERENTES
Si quieres saber si db1.tb1
y db2.tb2
son diferentes, ejecuta esto
SELECT IF(COUNT(1)>0,'Differences','No Differences') Comparison FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE
(
(table_schema='db1' AND table_name='tb1') OR
(table_schema='db2' AND table_name='tb2')
)
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
Si realmente necesita ver las diferencias, ejecute esto
SELECT column_name,ordinal_position,data_type,column_type FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE
(
(table_schema='db1' AND table_name='tb1') OR
(table_schema='db2' AND table_name='tb2')
)
AND table_name IN ('product_today','product_yesterday')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
DARLE UNA OPORTUNIDAD !!!
Puede comparar la suma de comprobación de la salida de SHOW CREATE TABLE product_today
# mysql -NBe "SHOW CREATE TABLE sakila.actor"| sed -r 's/AUTO_INCREMENT=[0-9]+/AUTO_INCREMENT=XXX/g' | md5sum
# 1bc0d72b294d1a93ce01b9a2331111cc -
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