Luego de de una larga recopilación de datos pudimos resolver este contratiempo que presentan ciertos de nuestros usuarios. Te regalamos la respuesta y esperamos servirte de gran ayuda.
Ejemplo 1: cómo obtener valores duplicados de array en javascript
var array =[1,2,2,3,3,4,5,6,2,3,7,8,5,22,1,2,511,12,50,22];console.log([...newSet(
array.filter((value, index, self)=> self.indexOf(value)!== index))]);
Ejemplo 2: contar duplicados array js
uniqueCount =["a","b","c","d","d","e","a","b","c","f","g","h","h","h","e","a"];var count =;
uniqueCount.forEach(function(i)0)+1;);console.log(count);
Ejemplo 3: javascript encuentra duplicado en array
// JavaScript - finds if there is duplicate in an array. // Returns True or False.constisThereADuplicate=function(arrayOfNumbers)// Create an empty associative array or hash. // This is preferred,let counts =;// // but this also works. Comment in below and comment out above if you want to try.// let counts = [];for(var i =0; i <= arrayOfNumbers.length; i++)// As the arrayOfNumbers is being iterated through,// the counts hash is being populated.// Each value in the array becomes a key in the hash. // The value assignment of 1, is there to complete the hash structure.// Once the key exists, meaning there is a duplicate, return true.// If there are no duplicates, the if block completes and returns false.if(counts[arrayOfNumbers[i]]===undefined)
counts[arrayOfNumbers[i]]=1;elsereturntrue;returnfalse;
Ejemplo 4: cómo obtener valores duplicados de array en javascript
var input =[1,2,3,1,3,1];var duplicates = input.reduce(function(acc, el, i, arr)if(arr.indexOf(el)!== i && acc.indexOf(el)<0) acc.push(el);return acc;,[]);document.write(duplicates);// = 1,3 (actual array == [1, 3])
Ejemplo 5: crear javascript array con valores repetidos
Array(5).fill(2)//=> [2, 2, 2, 2, 2]
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