actualizar div usando jquery sin volver a cargar el ejemplo de código de página

Hola, hemos encontrado la solución a lo que buscas, continúa leyendo y la obtendrás a continuación.

Ejemplo 1: ¿Cómo puedo actualizar una página con jQuery?

$('#something').click(function()location.reload(););

Ejemplo 2: actualizar un div jquery

$(document).ready(function()$(function()$('#ideal_form').submit(function(e)
                e.preventDefault();var form =$(this);var post_url = form.attr('action');var post_data = form.serialize();$('#loader3', form).html('





       Please wait...');
                $.ajax(
                    type:'POST',
                    url: post_url, 
                    data: post_data,success:function(msg)$(form).fadeOut(800,function()
                            form.html(msg).fadeIn().delay(2000););););););

Ejemplo 3: página de actualización de jquery sin recargar

In general,if you don't know how something works, look for an example which you can learn from.Forthis problem, consider thisDEMOYou can see loading content withAJAX is very easily accomplished with jQuery:$(function()// don't cache ajax or content won't be fresh
    $.ajaxSetup(
        cache:false);var ajax_load ="";// load() functionsvar loadUrl ="http://fiddle.jshell.net/deborah/pkmvD/show/";$("#loadbasic").click(function()$("#result").html(ajax_load).load(loadUrl););// end  );Try to understand how this works and then try replicating it.Good luck.You can find the corresponding tutorial HEREUpdateRight now the following event starts the ajax load function:$("#loadbasic").click(function()$("#result").html(ajax_load).load(loadUrl););You can also dothis periodically:How to fire AJAX request Periodically?(functionworker()
  $.ajax(
    url:'ajax/test.html',success:function(data)$('.result').html(data);,complete:function()// Schedule the next request when the current one's completesetTimeout(worker,5000););)();I made a demo ofthis implementation for you HERE.Inthis demo, every 2seconds(setTimeout(worker,2000);) the content is updated.You can also just load the data immediately:$("#result").html(ajax_load).load(loadUrl);Which has THIS corresponding demo.

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